[解法(해법)] 기계재료학 (공업재료) 3판(Engineering Materials 1, Ashby 출판사 BH)
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[解法(해법)] 기계재료학 (공업재료) 3판(Engineering Materials 1, Ashby 출판사 BH)
where CA and CB are the current rates of consumption t = t0 and Pt and
Examples: aluminium for copper as a conductor; reinforced concrete for wood,
Engineering Materials I
(b) The doubling time, tD, is calculated by setting Ct = t = 2C0, giving
platinum as a catalyst in chemical processing; etc. A long development time
Substitution
SOLUTIONS MANUAL
Substitution of the values given for r in the table into this equation gives the
t
r
Download : [솔루션] 기계재료학 (공업재료) 3.pdf( 32 )
레포트 > 공학,기술계열
and Design, 3rd edn
stone or cast-iron in construction; plastics for glass or metals as containers. For
by building large plant (economy of scale); using high-strength materials; use
rB
Solutions to Examples
기계, 공학, 과학, 연습문제, 솔루션, 재료
1
CA
tD
in cutting tools and lighting (a fluorescent tube contains more tungsten, as
r
Recycling
rA
a starter filament, than an incandescent bulb!); lead in lead-acid batteries;
다.
2 Solutions Manual: Engineering Materials I
Design to use proportionally smaller amounts of scarce materials, for example,
설명
ln
Qt are the values at t = t . Equating and solving for t gives
순서
t
re-designed to make recycling easier, and new recycling processes developed,
The fraction of material recycled is obviously important. Products may be
2.2. Principal conservation measures (see Section 2.7):
(c) Using the equation of Answer (a) we find that aluminium overtakes steel
in 201 years; polymers overtake steel in 55 years.
doubling times as 35, 23 and 18 years respectively.
2.1. (a) For commodity A Pt = CA exp
certain specific uses, most elements are not easily replaced. Examples: tungsten
t = 100
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![[솔루션] 기계재료학 (공업재료) 3-2312_02_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_02_.gif)
![[솔루션] 기계재료학 (공업재료) 3-2312_03_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_03_.gif)
![[솔루션] 기계재료학 (공업재료) 3-2312_04_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_04_.gif)
![[솔루션] 기계재료학 (공업재료) 3-2312_05_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_05_.gif)
An Introduction to Properties, Applications
= 100
More Economic Design
CB
but development time is again important.
of surface coatings to prevent metal loss by corrosion (e.g. in motor cars).
100
(up to 25 years) may be needed to find a replacement.
ln 2 ≈ 70
many applications, substitutes are easily found at small penalty of cost. But in
100
−rA
rB
and for commodity B Qt = CB exp
(아래는 해답 표지 부분과 2장의 일부 연습문제 부분입니다.
